Pass function as argument in Java

This is an example of passing function as argument in java. It kind of ugly but it can solve my duplicate code problem as below:

Before

public class BinaryTest {

	public static void main(String[] args) {

		byte[] bs = "gailo".getBytes();

		System.out.println("oct: " + toOct(bs));
		System.out.println("binary: " + toBin(bs));
		System.out.println("hex: " + toHex(bs));

	}

	private static String toOct(byte[] bs) {
		StringBuilder sb = new StringBuilder();
		for (byte b : bs) {
			sb.append(b);
			sb.append(" ");
		}
		return sb.toString();
	}

	private static String toBin(byte[] bs) {
		StringBuilder sb = new StringBuilder();
		for (byte b : bs) {
			sb.append(Integer.toBinaryString(b));
			sb.append(" ");
		}
		return sb.toString();
	}

	private static String toHex(byte[] bs) {
		StringBuilder sb = new StringBuilder();
		for (byte b : bs) {
			sb.append(Integer.toHexString(b));
			sb.append(" ");
		}
		return sb.toString();
	}

}

After

import com.google.common.base.Function;

public class BinaryTest {

	public static void main(String[] args) {

		byte[] bs = "gailo".getBytes();

		System.out.println("oct: " + toString(bs, new Function<Integer, String>() {

			@Override
			public String apply(Integer input) {
				return input.toString();
			}
		}));

		System.out.println("binary: " + toString(bs, new Function<Integer, String>() {

			@Override
			public String apply(Integer input) {
				return Integer.toBinaryString(input);
			}

		}));

		System.out.println("hex: " + toString(bs, new Function<Integer, String>() {

			@Override
			public String apply(Integer input) {
				return Integer.toHexString(input);
			}
		}));

	}

	private static String toString(byte[] bs, Function<Integer, String> function) {
		StringBuilder sb = new StringBuilder();
		for (byte b : bs) {
			sb.append(function.apply(new Integer(b)));
			sb.append(" ");
		}
		return sb.toString();
	}

}